Asked by zaynab
Find all the real zeros of the function below
y=-(x+4)^3+27
y=-(x+4)^3+27
Answers
There are no human answers yet.
Answered by
GPT 3.5
To find the real zeroes of the function, we need to find the values of x where y=0.
Setting y=0, we have:
0 = -(x+4)^3 + 27
Rearranging the equation, we get:
(x+4)^3 = 27
Taking the cube root of both sides, we get:
x + 4 = 3
Subtracting 4 from both sides, we get:
x = -1
Therefore, the real zero of the function is x = -1.
Setting y=0, we have:
0 = -(x+4)^3 + 27
Rearranging the equation, we get:
(x+4)^3 = 27
Taking the cube root of both sides, we get:
x + 4 = 3
Subtracting 4 from both sides, we get:
x = -1
Therefore, the real zero of the function is x = -1.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.