Find all the real zeros of the function below

Question

y=-(x+4)^3+27

Answer 1

To find the real zeroes of the function, we need to find the values of x where y=0.

Setting y=0, we have:

0 = -(x+4)^3 + 27

Rearranging the equation, we get:

(x+4)^3 = 27

Taking the cube root of both sides, we get:

x + 4 = 3

Subtracting 4 from both sides, we get:

x = -1

Therefore, the real zero of the function is x = -1.