To find the equation in slope-intercept form, we need to find the slope (m) and the y-intercept (b).
First, let's find the slope of the line using the formula:
m = (y2 - y1)/(x2 - x1)
Given the points (1, -3) and (3, 1), we have:
m = (1 - (-3))/(3 - 1)
m = 4/2
m = 2
Now, we have the slope (m = 2).
Next, we can use the slope-intercept form of a linear equation, y = mx + b, to find the y-intercept (b).
Choose one of the given points to substitute into the equation.
Let's use (1, -3).
-3 = 2(1) + b
-3 = 2 + b
b = -3 - 2
b = -5
Now we have the slope (m = 2) and the y-intercept (b = -5).
The equation in slope-intercept form is: y = 2x - 5
What is an equation in slope-intercept form for the line that passes through the points (1, –3) and (3, 1)?(1 point)Responsesy = 3x + 1y = 3 x + 1y = x – 3y = x – 3y = 2x + 5y = 2 x + 5y = 2x – 5
1 answer