Subtract (3b−2c)−(6c+2b)−(b+c)

Answer 1

To subtract the given expression, we will simplify each set of parentheses separately, and then combine like terms.

Step 1: Simplify the first set of parentheses:
(3b - 2c) = 3b - 2c

Step 2: Simplify the second set of parentheses:
(6c + 2b) = 6c + 2b

Step 3: Simplify the third set of parentheses:
(b + c) = b + c

Step 4: Subtract each set of parentheses:
(3b - 2c) - (6c + 2b) - (b + c) = 3b - 2c - 6c - 2b - b - c

Step 5: Combine like terms:
3b - 2c - 6c - 2b - b - c = (3b - 2b - b) + (-2c - 6c - c)
= 0b - 9c
= -9c

Therefore, the simplified form of (3b - 2c) - (6c + 2b) - (b + c) is -9c.