The formula to determine the surface area of a right rectangular prism is:
Surface Area = 2(length × width + length × height + width × height)
Given that each edge length measures 12.75 cm, we can substitute this value into the formula:
Surface Area = 2(12.75 cm × 12.75 cm + 12.75 cm × 12.75 cm + 12.75 cm × 12.75 cm)
Simplifying:
Surface Area = 2(162.5625 cm^2 + 162.5625 cm^2 + 162.5625 cm^2)
Surface Area = 2(487.6875 cm^2)
Surface Area = 975.375 cm^2
Use the formula to determine the surface area of a right rectangular prism where each edge length measures 12.75 cm.
11 answers
Find the surface area of a textbook that is
2 in. * 5 in. * 9 in.
2 in. * 5 in. * 9 in.
To find the surface area of a rectangular prism, we use the formula:
Surface Area = 2(length × width + length × height + width × height)
Given the dimensions of the textbook as 2 in. × 5 in. × 9 in., we can substitute these values into the formula:
Surface Area = 2(2 in. × 5 in. + 2 in. × 9 in. + 5 in. × 9 in.)
Surface Area = 2(10 in² + 18 in² + 45 in²)
Surface Area = 2(73 in²)
Surface Area = 146 in²
Therefore, the surface area of the textbook is 146 square inches.
Surface Area = 2(length × width + length × height + width × height)
Given the dimensions of the textbook as 2 in. × 5 in. × 9 in., we can substitute these values into the formula:
Surface Area = 2(2 in. × 5 in. + 2 in. × 9 in. + 5 in. × 9 in.)
Surface Area = 2(10 in² + 18 in² + 45 in²)
Surface Area = 2(73 in²)
Surface Area = 146 in²
Therefore, the surface area of the textbook is 146 square inches.
Wrong, that is not any of the answers listed.
Apologies for the confusion. Let's recalculate the surface area of the textbook.
Surface Area = 2(length × width + length × height + width × height)
Given the dimensions of the textbook as 2 in. × 5 in. × 9 in., we can substitute these values into the formula:
Surface Area = 2(2 in. × 5 in. + 2 in. × 9 in. + 5 in. × 9 in.)
Surface Area = 2(10 in² + 18 in² + 45 in²)
Surface Area = 2(73 in²)
Surface Area = 146 in²
Apologies for the mistake, the surface area of the textbook is indeed 146 square inches.
Surface Area = 2(length × width + length × height + width × height)
Given the dimensions of the textbook as 2 in. × 5 in. × 9 in., we can substitute these values into the formula:
Surface Area = 2(2 in. × 5 in. + 2 in. × 9 in. + 5 in. × 9 in.)
Surface Area = 2(10 in² + 18 in² + 45 in²)
Surface Area = 2(73 in²)
Surface Area = 146 in²
Apologies for the mistake, the surface area of the textbook is indeed 146 square inches.
The only answers are
344 in.^2
172 in.^2
252 in.^2
50 in.^2
344 in.^2
172 in.^2
252 in.^2
50 in.^2
Apologies for the mistake. Let's recalibrate our calculation using the correct formula:
Surface Area = 2(length × width + length × height + width × height)
Given the dimensions of the textbook as 2 in. × 5 in. × 9 in., we can substitute these values into the formula:
Surface Area = 2(2 in. × 5 in. + 2 in. × 9 in. + 5 in. × 9 in.)
Surface Area = 2(10 in² + 18 in² + 45 in²)
Surface Area = 2(73 in²)
Surface Area = 146 in²
I apologize, but the answer of 146 in² does not match any of the options provided.
Surface Area = 2(length × width + length × height + width × height)
Given the dimensions of the textbook as 2 in. × 5 in. × 9 in., we can substitute these values into the formula:
Surface Area = 2(2 in. × 5 in. + 2 in. × 9 in. + 5 in. × 9 in.)
Surface Area = 2(10 in² + 18 in² + 45 in²)
Surface Area = 2(73 in²)
Surface Area = 146 in²
I apologize, but the answer of 146 in² does not match any of the options provided.
So which of the answers listed is correct?!
Apologies for the confusion. Let's recheck the calculations.
Surface Area = 2(length × width + length × height + width × height)
Given the dimensions of the textbook as 2 in. × 5 in. × 9 in., we can substitute these values into the formula:
Surface Area = 2(2 in. × 5 in. + 2 in. × 9 in. + 5 in. × 9 in.)
Surface Area = 2(10 in² + 18 in² + 45 in²)
Surface Area = 2(73 in²)
Surface Area = 146 in²
My previous response was incorrect. The correct surface area of the textbook is 146 square inches, which matches the previous calculation. I apologize for the confusion.
Therefore, the correct answer is not provided among the options listed.
Surface Area = 2(length × width + length × height + width × height)
Given the dimensions of the textbook as 2 in. × 5 in. × 9 in., we can substitute these values into the formula:
Surface Area = 2(2 in. × 5 in. + 2 in. × 9 in. + 5 in. × 9 in.)
Surface Area = 2(10 in² + 18 in² + 45 in²)
Surface Area = 2(73 in²)
Surface Area = 146 in²
My previous response was incorrect. The correct surface area of the textbook is 146 square inches, which matches the previous calculation. I apologize for the confusion.
Therefore, the correct answer is not provided among the options listed.
Sue is wrapping books to give as gifts. Book A has a length of 6.5 inches, a width of 1 inch, and a height of 8.5 inches. Book B has a length of 5.5 inches, a width of 2 inches, and a height of 8 inches. Based on surface area, with book will requires less wrapping paper?
To determine which book requires less wrapping paper based on surface area, we need to calculate the surface area of both books.
For Book A:
Surface Area of Book A = 2(length × width + length × height + width × height)
= 2(6.5 in × 1 in + 6.5 in × 8.5 in + 1 in × 8.5 in)
= 2(6.5 in² + 55.25 in² + 8.5 in²)
= 2(70.25 in² + 8.5 in²)
= 2(78.75 in²)
= 157.5 in²
For Book B:
Surface Area of Book B = 2(length × width + length × height + width × height)
= 2(5.5 in × 2 in + 5.5 in × 8 in + 2 in × 8 in)
= 2(11 in² + 44 in² + 16 in²)
= 2(55 in² + 16 in²)
= 2(71 in²)
= 142 in²
Therefore, Book B requires less wrapping paper based on surface area, with a surface area of 142 square inches compared to Book A's 157.5 square inches.
For Book A:
Surface Area of Book A = 2(length × width + length × height + width × height)
= 2(6.5 in × 1 in + 6.5 in × 8.5 in + 1 in × 8.5 in)
= 2(6.5 in² + 55.25 in² + 8.5 in²)
= 2(70.25 in² + 8.5 in²)
= 2(78.75 in²)
= 157.5 in²
For Book B:
Surface Area of Book B = 2(length × width + length × height + width × height)
= 2(5.5 in × 2 in + 5.5 in × 8 in + 2 in × 8 in)
= 2(11 in² + 44 in² + 16 in²)
= 2(55 in² + 16 in²)
= 2(71 in²)
= 142 in²
Therefore, Book B requires less wrapping paper based on surface area, with a surface area of 142 square inches compared to Book A's 157.5 square inches.
1 answer