Asked by Physics (algebra bit)

rearanging

V^2 = Vo^2 + 2 a (X - Xo)

for V gives me

V = (Vo^2 + 2 a (X - Xo))^(2^-1)

or this

V = (Vo + 2 a (X - Xo))^(2^-1)

How come Vo^2 dosen't become Vo
Answered by drwls
It is rather unusual to write 2^-1 for 1/2, but either is OK.

Vo^2 is not V^2 because the equation says that it isn't. The reasons are due to physics. Velocity decreases when there is deceleration.

Vo^2 can never become V. They have different dimensions. One is squared and the other isn't.
Answered by QUESTION
I didn't right Vo^2 as V...
Answered by drwls
This is what you wrote:
<<How come Vo^2 dosen't become Vo >>
Answered by QUESTION
I agree and as you can see I wrote "...Vo^2 dosen't become Vo"

not

""...Vo^2 dosen't become V"
Answered by bobpursley
V^2 = Vo^2 + 2 a (X - Xo)

V= sqrt ( Vo^2 + 2 a (X - Xo)


Your algebra is totally wrong.


Answered by Damon
The initial speed squared Vo^2 is in meters^2/seconds^2
The final speed V is in meters/second
They can never, ever be the same as drwls said.
Answered by Damon
Nor can Vo^2 be Vo for the same reason.
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