To find the surface area of each book, we need to calculate the area of each face and then add them up.
For Book A:
-The front and back faces each have dimensions 6.5 inches by 8.5 inches, so their combined area is 6.5 * 8.5 * 2 = 110.5 square inches.
-The top and bottom faces each have dimensions 6.5 inches by 1 inch, so their combined area is 6.5 * 1 * 2 = 13 square inches.
-The two side faces each have dimensions 8.5 inches by 1 inch, so their combined area is 8.5 * 1 * 2 = 17 square inches.
Therefore, the total surface area of Book A is 110.5 + 13 + 17 = 140.5 square inches.
For Book B:
-The front and back faces each have dimensions 5.5 inches by 8 inches, so their combined area is 5.5 * 8 * 2 = 88 square inches.
-The top and bottom faces each have dimensions 5.5 inches by 2 inches, so their combined area is 5.5 * 2 * 2 = 22 square inches.
-The two side faces each have dimensions 8 inches by 2 inches, so their combined area is 8 * 2 * 2 = 32 square inches.
Therefore, the total surface area of Book B is 88 + 22 + 32 = 142 square inches.
Based on surface area, Book A will require less wrapping paper since its total surface area is 140.5 square inches, while Book B's total surface area is 142 square inches.
Sue is wrapping books to give as gifts. Book A has a length of 6.5 inches, a width of 1 inch, and a height of 8.5 inches. Book B has a length of 5.5 inches, a width of 2 inches, and a height of 8 inches. Based on surface area, which book will require less wrapping paper?(1 point)
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