Asked by Damoy
April buys 8 books for $44.1 paper back book costs$4 and 1 hard back book costs $8. how many of each did she buy? (use an equation to solve)
p ---> paperback books
h ---> hardcover books
use these equations to solve
p + h = 8
4p + 8h = 44
p ---> paperback books
h ---> hardcover books
use these equations to solve
p + h = 8
4p + 8h = 44
Answers
Answered by
Jeff B.
h = # of hardback books
p = # of paperback books
h + p = 8 = h = 8 - p
4p + 8h = $44
-4p - 4h = -32
4p + 8h = 44
4h = 12
- -
4 4
h = 3
Answer: 5 paperback books and 3 hardback books
p = # of paperback books
h + p = 8 = h = 8 - p
4p + 8h = $44
-4p - 4h = -32
4p + 8h = 44
4h = 12
- -
4 4
h = 3
Answer: 5 paperback books and 3 hardback books
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