Asked by thx
Mr. Yamamoto has a piece of plywood that is 15 1/ 2 ft. long and 12 3/4 ft. wide. He needs to cut the wood into 12 pieces for the students in his carpentry class. Mr. Yamamoto cuts the length into 4 equal pieces and the width into 3 equal pieces. What are the dimensions of each piece? Express the answers in simplest form.
Answers
Answered by
GPT 3.5
To find the length of each piece, we divide the total length of the plywood by the number of pieces:
$\dfrac{15 \frac{1}{2}\text{ ft}}{4} = \dfrac{31}{2}\div4 = \dfrac{31}{2}\div2 = \dfrac{31}{4} = 7\frac{\text{3}}{4}\text{ ft}$
So each piece is $\boxed{7\frac{3}{4}}$ ft long.
To find the width of each piece, we divide the total width of the plywood by the number of pieces:
$\dfrac{12\frac{3}{4}\text{ ft}}{3} = \dfrac{51}{4}\div3 = \dfrac{51}{4}\div3 = \dfrac{51}{12} = 4\frac{3}{12} = 4\frac{1}{4}\text{ ft}$.
So each piece is $\boxed{4\frac{1}{4}}$ ft wide.
$\dfrac{15 \frac{1}{2}\text{ ft}}{4} = \dfrac{31}{2}\div4 = \dfrac{31}{2}\div2 = \dfrac{31}{4} = 7\frac{\text{3}}{4}\text{ ft}$
So each piece is $\boxed{7\frac{3}{4}}$ ft long.
To find the width of each piece, we divide the total width of the plywood by the number of pieces:
$\dfrac{12\frac{3}{4}\text{ ft}}{3} = \dfrac{51}{4}\div3 = \dfrac{51}{4}\div3 = \dfrac{51}{12} = 4\frac{3}{12} = 4\frac{1}{4}\text{ ft}$.
So each piece is $\boxed{4\frac{1}{4}}$ ft wide.
Answered by
GPT 3.5
The dimensions of each piece are:
Length: 7 3/4 ft
Width: 4 1/4 ft
Length: 7 3/4 ft
Width: 4 1/4 ft
Answered by
GPT 3.5
Apologies for the error.
The correct dimensions of each piece are:
Length: 3 7/8 ft
Width: 4 1/4 ft
The correct dimensions of each piece are:
Length: 3 7/8 ft
Width: 4 1/4 ft
Answered by
GPT 3.5
Thank you for your understanding.