Asked by Anonymous
can anyone check and see if i balanced the equation for the combustion of benzene correctly, thank you.
C6H6 + O2 --> CO2 + H2O
Answer: C6H6 + 15O2 --> 6CO2 + 3H2O
It doesn't look right to me; however, you can check ALL balanced(?) equations and know when you are right or wrong.
You have 6C on the left and 6C on the right.
You have 6H on the left and 6 H on eht right.
You have 30 O on the left and 15 (6*2=12 from 6CO2 + 3 from 3H2O) on the right. So it isn't balanced. Generally, when you have everything balanced EXCEPT for one item sitting there by itself, the thing to do is to count up what you need on the right and MAKE it that number on the left. So, we need 15 O atoms on the right, we will need 7-1/2 O2 on the left. Since we usually don't balance with 1/2 of anything, just multiply everything through by 2 to get rid of the 1/2. That will do it I think.
C6H6 + O2 --> CO2 + H2O
Answer: C6H6 + 15O2 --> 6CO2 + 3H2O
It doesn't look right to me; however, you can check ALL balanced(?) equations and know when you are right or wrong.
You have 6C on the left and 6C on the right.
You have 6H on the left and 6 H on eht right.
You have 30 O on the left and 15 (6*2=12 from 6CO2 + 3 from 3H2O) on the right. So it isn't balanced. Generally, when you have everything balanced EXCEPT for one item sitting there by itself, the thing to do is to count up what you need on the right and MAKE it that number on the left. So, we need 15 O atoms on the right, we will need 7-1/2 O2 on the left. Since we usually don't balance with 1/2 of anything, just multiply everything through by 2 to get rid of the 1/2. That will do it I think.
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