To solve this problem, we need to isolate the variable x.
Given x + 33 = y + 22, we can start by subtracting 33 from both sides of the equation:
x + 33 - 33 = y + 22 - 33
Simplifying this equation gives us:
x = y - 11
Now that we have isolated x, we can cube both sides of the equation to find x^3:
(x)^3 = (y - 11)^3
Expanding the right side using the binomial expansion formula gives us:
x^3 = y^3 - 3y^2(11) + 3y(11^2) - 11^3
Simplifying this equation gives us:
x^3 = y^3 - 33y^2 + 363y - 1331
Therefore, x^3 = y^3 - 33y^2 + 363y - 1331.
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
If x+33=y+22
,then x3=_______.
1 answer