To determine the Ka for the weak acid, we first need to convert the pH to the concentration of the hydronium ion ([H3O+]) in the solution.
The pH is given as 3.86, which means that the hydronium ion concentration ([H3O+]) is 10^-pH.
[H3O+] = 10^-3.86
[H3O+] = 1.39 x 10^-4
Now, we can use the concentration of the weak acid (0.38 M) and the hydronium ion concentration to determine the Ka.
Ka = [H3O+][A-] / [HA]
Since we know that the concentration of the weak acid ([HA]) is 0.38 M, and the concentration of the hydronium ion ([H3O+]) is 1.39 x 10^-4 M, we can substitute these values into the equation:
Ka = (1.39 x 10^-4)(0.38) / 0.38
Simplifying the equation, we find:
Ka = 1.39 x 10^-4
Therefore, the Ka for this weak acid is 1.39 x 10^-4.
A weak acid solution has a pH of 3.86. if the acid solution has a concentration of 0.38, what would the Ka be for this acid
1 answer