solve 0 = -16t^2 + 50

Answer 1

To solve the equation -16t^2 + 50 = 0, we can use the quadratic formula:

t = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = -16, b = 0, and c = 50. Substituting these values into the quadratic formula, we get:

t = (-(0) ± √((0)^2 - 4(-16)(50))) / (2(-16))

t = (± √(0 - (-3200))) / (-32)

t = (± √(3200)) / (-32)

t = ± √(3200) / (-32)

To simplify further, we can find the square root of 3200:

√(3200) = √(16 * 200) = 4√(200)

Substituting this value back into the equation:

t = ± 4√(200) / (-32)

Simplifying further:

t = ± √(200) / (-8)

Therefore, the solution to the equation -16t^2 + 50 = 0 is:

t = √(200) / -8 or t = -√(200) / 8