To find the equation of a line that is perpendicular to y = 5x - 7, we need to find its slope. The slope of the given line is 5, so the slope of the line perpendicular to it would be the negative reciprocal of 5, which is -1/5.
We are given that the line passes through (-10, 3), so we can substitute these coordinates into the equation y = mx + b and solve for b.
3 = (-1/5)(-10) + b
3 = 2 + b
b = 1
Therefore, the equation of the line that passes through (-10, 3) and is perpendicular to y = 5x - 7 is y = -1/5x + 1.
Answer: y = -1/5x + 1
Which equation is the equation of a line that passes through (–10, 3) and is perpendicular to y = 5x – 7? (1 point) Responses y = 5x + 53 y = 5 x + 53 y = –one-fifthx – 7 y = – Image with alt text: one-fifth x – 7 y = –one-fifthx + 1 y = – Image with alt text: one-fifth x + 1 y = one-fifthx + 5
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