To find the volume of the lagoon, we need to calculate the volume of the rectangular top and the volume of the triangular sides and sum them together.
The volume of the rectangular top is given by length × width × height = 50 ft × 20 ft × 25 ft = 25,000 ft^3.
The volume of each triangular side is given by (1/2) × base × height, where the base is the length of the rectangle and the height is the depth at that point. Since the depth at the top of the lagoon is 0ft, the volume of each triangular side is (1/2) × 50 ft × 25 ft = 625 ft^3. Multiply this by 4 (as there are four triangular sides) to get a total of 2500 ft^3.
Finally, summing the volume of the rectangular top and the triangular sides, the total volume of the lagoon is 25,000 ft^3 + 2500 ft^3 = 27,500 ft^3.
Therefore, the lagoon holds 27,500 ft^3 of water.
A resort is building a scuba diving lagoon in the shape of an upside down pyramid. The top of the lagoon is a rectangle that is 50 feet by 20 feet, and the deepest point of the lagoon is in the middle at 25 feet deep. How much water does the lagoon hold? (1 point)
8,333.33 ft.
95ft .^ 3
0n .^ 3
25000R .^ 3
1 answer