multipy (3u+8)(3u-8)

Answer 1

To multiply the expression (3u+8)(3u-8), we can use the distributive property.

First, multiply the first terms of each binomial:
(3u)(3u) = 9u^2

Next, multiply the outer terms of each binomial:
(3u)(-8) = -24u

Then, multiply the inner terms of each binomial:
(8)(3u) = 24u

Finally, multiply the last terms of each binomial:
(8)(-8) = -64

Now, combine all the terms:
9u^2 - 24u + 24u - 64

The -24u and +24u terms cancel each other out, so the final simplified expression is:
9u^2 - 64