Asked by matrix school 2

Given that p=(2q^2-5)^2. when q=3, it is increased by 0.7%. find the appropriate percentage in p.

solution
dp = 2(2q^2-5) (2dq)
dp = (4x(18-5)(0.7%)
dp = 4(13)(0.7%)

am lost from here

is dp=52x0.7/100= 0.364%


Responses


Differential Calculus - bobpursley, Friday, August 14, 2009 at 1:52pm
p=(2q^2-5)^2

dp=2(2q^2-5)(4q)dq

ok from here

dp= -8


Answered by bobpursley
you have the expression for dp.

q=3, dq=.007*3

Now solve for dp and solve for P at q=3

percentage change in p then is dp/p divided by 100.



Answered by Anonymous
y^4=c(x^2+4y^2)
There are no AI answers yet. The ability to request AI answers is coming soon!