Question

5x + 5y = 140

3x + 9y = 162



What is the solution for the system of equations above?

Answer 1

To find the solution for this system of equations, we can use the method of elimination or substitution.

Using the elimination method, we can multiply the first equation by 3 and the second equation by -5 to obtain the same coefficient for y:

15x + 15y = 420
-15x - 45y = -810

Adding the two equations together, we can eliminate the x variable:

15x + 15y - 15x - 45y = 420 - 810
-30y = -390
y = (-390)/(-30)
y = 13

Substituting the value of y back into the first equation, we can solve for x:

5x + 5(13) = 140
5x + 65 = 140
5x = 140 - 65
5x = 75
x = 75/5
x = 15

Therefore, the solution for the system of equations is x = 15 and y = 13.