Asked by B.B.
Did I do this problem right?
Consider the experiment of drawing two cards without replacement from an ordinary deck of playing cards. What are the odds in favor of drawing a spade or a heart?
Answer: P(Spade)*P(Spade)=(13/52)x(13/51)=169/2652=0.06372. Is this right?
Thanks.
Consider the experiment of drawing two cards without replacement from an ordinary deck of playing cards. What are the odds in favor of drawing a spade or a heart?
Answer: P(Spade)*P(Spade)=(13/52)x(13/51)=169/2652=0.06372. Is this right?
Thanks.
Answers
Answered by
bobpursley
No, you did the probability of drawing two spades. As I read the question, you want the probabilitiy of one spade or one heart,
Pr= Pr(one spade and one club/diamond)+pr(heart and one club/diamond).
Pr=13/52* 26/51 + 13/52*26/51
check my thinking.
Pr= Pr(one spade and one club/diamond)+pr(heart and one club/diamond).
Pr=13/52* 26/51 + 13/52*26/51
check my thinking.
Answered by
B.B.
So, do I multiply 13/52*26/51 for both and then add?
Ex: 13/52*26/51+13/52*26/51=
338/2652+338/2652=
676/2652
Is this right?
Thanks.
Ex: 13/52*26/51+13/52*26/51=
338/2652+338/2652=
676/2652
Is this right?
Thanks.
Answered by
B.B
Did I do the problem right? Was the answer 676/2652?
Thanks.
Thanks.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.