No, you did the probability of drawing two spades. As I read the question, you want the probabilitiy of one spade or one heart,
Pr= Pr(one spade and one club/diamond)+pr(heart and one club/diamond).
Pr=13/52* 26/51 + 13/52*26/51
check my thinking.
Did I do this problem right?
Consider the experiment of drawing two cards without replacement from an ordinary deck of playing cards. What are the odds in favor of drawing a spade or a heart?
Answer: P(Spade)*P(Spade)=(13/52)x(13/51)=169/2652=0.06372. Is this right?
Thanks.
3 answers
So, do I multiply 13/52*26/51 for both and then add?
Ex: 13/52*26/51+13/52*26/51=
338/2652+338/2652=
676/2652
Is this right?
Thanks.
Ex: 13/52*26/51+13/52*26/51=
338/2652+338/2652=
676/2652
Is this right?
Thanks.
Did I do the problem right? Was the answer 676/2652?
Thanks.
Thanks.