Question

(3b−2c)−(6c+2b)−(b+c) .

Answer 1

First, let's simplify each expression within the parentheses:

(3b - 2c) becomes 3b - 2c
(6c + 2b) becomes 6c + 2b
(b + c) becomes b + c

Now we can subtract the second expression from the first:

(3b - 2c) - (6c + 2b) becomes 3b - 2c - 6c - 2b

Now let's simplify further:

3b - 2c - 6c - 2b becomes (3b - 2b) - (2c + 6c)

Simplifying even further:

3b - 2b becomes b
2c + 6c becomes 8c

Therefore, the final simplified expression is b - 8c.