Asked by connexus user
Lucy saws a wooden rod into two pieces. The larger piece is 7 3/4 inches long. The original rod was 9 1/8 inches long. How many inches long is the resulting smaller piece?(1 point)
Responses
2
16 7/8
2 5/8
1 3/8
Responses
2
16 7/8
2 5/8
1 3/8
Answers
Answered by
connexus user
Henry has a pot with 6 3/10 liters of water. He pours out 3 1/5 liters of water. How many liters of water remain in the pot?(1 point)
Responses
3 1/10
3 Start Fraction 1 over 10 End Fraction
9 1/2
9 Start Fraction 1 over 2 End Fraction
3 1/5
3 Start Fraction 1 over 5 End Fraction
2 9/10
Responses
3 1/10
3 Start Fraction 1 over 10 End Fraction
9 1/2
9 Start Fraction 1 over 2 End Fraction
3 1/5
3 Start Fraction 1 over 5 End Fraction
2 9/10
Answered by
GPT 3.5
To find the length of the smaller piece, we need to subtract the length of the larger piece from the original length of the rod.
Original length of the rod: 9 1/8 inches
Length of the larger piece: 7 3/4 inches
9 1/8 - 7 3/4 = 73/8 - 31/4 = (73 - 62)/8 = 11/8
So, the resulting smaller piece is 11/8 inches long.
However, this fraction can be simplified further.
11/8 = 1 3/8
Therefore, the resulting smaller piece is 1 3/8 inches long.
Original length of the rod: 9 1/8 inches
Length of the larger piece: 7 3/4 inches
9 1/8 - 7 3/4 = 73/8 - 31/4 = (73 - 62)/8 = 11/8
So, the resulting smaller piece is 11/8 inches long.
However, this fraction can be simplified further.
11/8 = 1 3/8
Therefore, the resulting smaller piece is 1 3/8 inches long.
Answered by
GPT 3.5
To find the amount of water remaining in the pot, we need to subtract the amount poured out from the initial amount.
Initial amount of water: 6 3/10 liters
Amount poured out: 3 1/5 liters
To subtract these mixed numbers, we need to convert them into improper fractions.
Initial amount of water: 6 3/10 = 63/10 liters
Amount poured out: 3 1/5 = 16/5 liters
Now, we subtract:
63/10 - 16/5 = (63*5 - 16*10)/50 = (315 - 160)/50 = 155/50
This fraction can be simplified further.
155/50 = 31/10 = 3 1/10
Therefore, there are 3 1/10 liters of water remaining in the pot.
Initial amount of water: 6 3/10 liters
Amount poured out: 3 1/5 liters
To subtract these mixed numbers, we need to convert them into improper fractions.
Initial amount of water: 6 3/10 = 63/10 liters
Amount poured out: 3 1/5 = 16/5 liters
Now, we subtract:
63/10 - 16/5 = (63*5 - 16*10)/50 = (315 - 160)/50 = 155/50
This fraction can be simplified further.
155/50 = 31/10 = 3 1/10
Therefore, there are 3 1/10 liters of water remaining in the pot.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.