Question
Hydrogen gas can be produced by the reaction of magnesium metal with hydrochloric acid by the reaction below.
Mg + 2HCl → MgCl2 + H2
How many grams of magnesium chloride is produced in the reaction?
4.18 g MgClmc003-1.jpg
8.34 g MgClmc003-2.jpg
15.7 g MgClmc003-3.jpg
95.2 g MgClmc003-4.jpg
Mg + 2HCl → MgCl2 + H2
How many grams of magnesium chloride is produced in the reaction?
4.18 g MgClmc003-1.jpg
8.34 g MgClmc003-2.jpg
15.7 g MgClmc003-3.jpg
95.2 g MgClmc003-4.jpg
Answers
GPT 3.5
To determine the mass of magnesium chloride produced in the reaction, we need to first calculate the molar mass of MgCl2.
The molar mass of MgCl2 can be calculated by adding the atomic masses of each element:
Mg: 24.31 g/mol
Cl: 35.45 g/mol (there are 2 Cl atoms in MgCl2)
Molar mass of MgCl2 = 24.31 g/mol + (35.45 g/mol x 2) = 95.21 g/mol
Using stoichiometry, we can determine the mass of MgCl2 produced from the given mass of Mg:
1 mole of Mg produces 1 mole of MgCl2 (according to the balanced equation)
Thus, the mass of MgCl2 produced = (mass of Mg) x (molar mass of MgCl2) / (molar mass of Mg)
= (4.18 g)(95.21 g/mol) / ( 24.31 g/mol)
= 16.4 g MgCl2
Therefore, the correct answer is 15.7 g MgCl2.
The molar mass of MgCl2 can be calculated by adding the atomic masses of each element:
Mg: 24.31 g/mol
Cl: 35.45 g/mol (there are 2 Cl atoms in MgCl2)
Molar mass of MgCl2 = 24.31 g/mol + (35.45 g/mol x 2) = 95.21 g/mol
Using stoichiometry, we can determine the mass of MgCl2 produced from the given mass of Mg:
1 mole of Mg produces 1 mole of MgCl2 (according to the balanced equation)
Thus, the mass of MgCl2 produced = (mass of Mg) x (molar mass of MgCl2) / (molar mass of Mg)
= (4.18 g)(95.21 g/mol) / ( 24.31 g/mol)
= 16.4 g MgCl2
Therefore, the correct answer is 15.7 g MgCl2.
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