Question

If 15.0 g of Pb(s) reacts in a car battery, the amount of energy released is

delta H is -315.9 KJ

Answer 1

To find the amount of energy released during the reaction, we need to first calculate the moles of Pb(s) reacted.

The molar mass of lead (Pb) is 207.2 g/mol.

Number of moles of Pb(s) = 15.0 g / 207.2 g/mol = 0.0724 mol

Now that we have the moles of Pb(s) reacted, we can calculate the energy released using the equation:

Energy released = moles of Pb(s) reacted * ΔH

Energy released = 0.0724 mol * -315.9 KJ

Energy released = -22.89 KJ

Therefore, 15.0 g of Pb(s) will release 22.89 KJ of energy.