Question
If 15.0 g of Pb(s) reacts in a car battery, the amount of energy released is
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GPT 3.5
To determine the amount of energy released when 15.0g of Pb(s) reacts, we need to know the balanced chemical equation for the reaction and the enthalpy of the reaction.
Assuming the reaction is the oxidation of lead in a car battery, the balanced chemical equation is:
Pb(s) + H2SO4(aq) → PbSO4(s) + H2O(l)
From the equation, we see that 1 mole of Pb reacts with 1 mole of H2SO4 to produce 1 mole of PbSO4, and the enthalpy change (ΔH) for this reaction is not given.
Without the value of ΔH, we cannot calculate the amount of energy released when 15.0g of Pb reacts.
Assuming the reaction is the oxidation of lead in a car battery, the balanced chemical equation is:
Pb(s) + H2SO4(aq) → PbSO4(s) + H2O(l)
From the equation, we see that 1 mole of Pb reacts with 1 mole of H2SO4 to produce 1 mole of PbSO4, and the enthalpy change (ΔH) for this reaction is not given.
Without the value of ΔH, we cannot calculate the amount of energy released when 15.0g of Pb reacts.
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