Question
Which conical container holds more water?
cone 1
4 cm on base
8 cm on vertical slant height
cone 2
8 cm on vertical slant height
6cm on base
Figure not drawn to scale.
cone 1
4 cm on base
8 cm on vertical slant height
cone 2
8 cm on vertical slant height
6cm on base
Figure not drawn to scale.
Answers
GPT 3.5
To determine which conical container holds more water, we need to calculate the volume of each cone using the given measurements.
The formula to calculate the volume of a cone is:
V = (1/3) * π * r^2 * h
Let's calculate the volume for each cone:
Cone 1:
We are given that the base has a diameter (and hence, radius) of 4 cm. The vertical slant height is given as 8 cm.
Radius (r) = 4 cm / 2 = 2 cm
Height (h) = 8 cm
V1 = (1/3) * π * 2^2 * 8
V1 = (1/3) * π * 4 * 8
V1 = (4/3) * π * 8
V1 = 32π/3 ≈ 33.51 cm^3 (rounded to two decimal places)
Cone 2:
We are given that the base has a diameter (and hence, radius) of 6 cm. The vertical slant height is given as 8 cm.
Radius (r) = 6 cm / 2 = 3 cm
Height (h) = 8 cm
V2 = (1/3) * π * 3^2 * 8
V2 = (1/3) * π * 9 * 8
V2 = (3/3) * π * 9 * 8
V2 = 24π ≈ 75.40 cm^3 (rounded to two decimal places)
Therefore, Cone 2 holds more water as it has a larger volume compared to Cone 1.
The formula to calculate the volume of a cone is:
V = (1/3) * π * r^2 * h
Let's calculate the volume for each cone:
Cone 1:
We are given that the base has a diameter (and hence, radius) of 4 cm. The vertical slant height is given as 8 cm.
Radius (r) = 4 cm / 2 = 2 cm
Height (h) = 8 cm
V1 = (1/3) * π * 2^2 * 8
V1 = (1/3) * π * 4 * 8
V1 = (4/3) * π * 8
V1 = 32π/3 ≈ 33.51 cm^3 (rounded to two decimal places)
Cone 2:
We are given that the base has a diameter (and hence, radius) of 6 cm. The vertical slant height is given as 8 cm.
Radius (r) = 6 cm / 2 = 3 cm
Height (h) = 8 cm
V2 = (1/3) * π * 3^2 * 8
V2 = (1/3) * π * 9 * 8
V2 = (3/3) * π * 9 * 8
V2 = 24π ≈ 75.40 cm^3 (rounded to two decimal places)
Therefore, Cone 2 holds more water as it has a larger volume compared to Cone 1.