We have the quadratic equation: -6x^2 - x - 12 = -6
Rearranging the equation, we get: -6x^2 - x - 12 + 6 = 0
Simplifying, we have: -6x^2 - x - 6 = 0
Now we can determine the discriminant, which is given by the formula: D = b^2 - 4ac
In our equation, a = -6, b = -1, and c = -6.
Substituting the values into the discriminant formula: D = (-1)^2 - 4(-6)(-6)
Simplifying further: D = 1 - 144
D = -143
Since the discriminant (-143) is negative, it means that there are no real solutions to this equation.
use the discriminate to determain the number of real solutions to each solution
-6x^2-x-12=-6
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