Asked by Anonymous
                The number of accidents that occur at the intersection
of Pine and Linden streets between 3 p.m. and
6 p.m. on Friday afternoons is 0, 1, 2, or 3, with probabilities
of 0.84, 0.13, 0.02, and 0.01, respectively.
Graph this probability distribution. What is the
expected value for the random variable given the
number of accidents?
            
        of Pine and Linden streets between 3 p.m. and
6 p.m. on Friday afternoons is 0, 1, 2, or 3, with probabilities
of 0.84, 0.13, 0.02, and 0.01, respectively.
Graph this probability distribution. What is the
expected value for the random variable given the
number of accidents?
Answers
                    Answered by
            Marth
            
    The expected value of the random accidents can be found by the summation of the number of accidents * their probabilities.
E(x) = 0*0.84 + 1*0.13 + 2*0.02 + 3*0.01
    
E(x) = 0*0.84 + 1*0.13 + 2*0.02 + 3*0.01
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.