Asked by Anonymous
The number of accidents that occur at the intersection
of Pine and Linden streets between 3 p.m. and
6 p.m. on Friday afternoons is 0, 1, 2, or 3, with probabilities
of 0.84, 0.13, 0.02, and 0.01, respectively.
Graph this probability distribution. What is the
expected value for the random variable given the
number of accidents?
of Pine and Linden streets between 3 p.m. and
6 p.m. on Friday afternoons is 0, 1, 2, or 3, with probabilities
of 0.84, 0.13, 0.02, and 0.01, respectively.
Graph this probability distribution. What is the
expected value for the random variable given the
number of accidents?
Answers
Answered by
Marth
The expected value of the random accidents can be found by the summation of the number of accidents * their probabilities.
E(x) = 0*0.84 + 1*0.13 + 2*0.02 + 3*0.01
E(x) = 0*0.84 + 1*0.13 + 2*0.02 + 3*0.01
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