Subtract 12(z+4)−3(14z+1) . Use fractions in final form

To solve this, we can distribute and combine like terms.

First, distribute 12 to both terms in (z+4):
12(z+4) = 12z + 48

Next, distribute 3 to both terms in (14z+1):
3(14z+1) = 42z + 3

Now, we can subtract the two expressions:
12z + 48 - (42z + 3)

To subtract, we can distribute the negative sign to both terms inside the parentheses:
12z + 48 - 42z - 3

Now we can combine like terms by grouping variables and constants:
(12z - 42z) + (48 - 3)

This simplifies to:
-30z + 45

Therefore, the final answer is -30z + 45.