6) 500J of work is required by a machine to raise a load of 250N through a vertical distance of 1.6m. the efficiency of the machine is (a) 80% (b) 75% (c) 67% (d) 50%

Answer 1

To find the efficiency of the machine, we can use the formula:

Efficiency = (useful output energy / input energy) * 100%

Given that the input energy is 500J and the machine is raising a load of 250N through a vertical distance of 1.6m, we can calculate the useful output energy:

Useful output energy = force * distance
= 250N * 1.6m
= 400J

Now we can calculate the efficiency:

Efficiency = (400J / 500J) * 100%
≈ 80%

Therefore, the efficiency of the machine is approximately 80%.

(a) 80%