To use the quadratic formula to solve the quadratic equation x^2 - 6x - 20 = 20, we first need to rearrange the equation so that it is in the form ax^2 + bx + c = 0.
x^2 - 6x - 40 = 0
Comparing this to the quadratic equation form, we have a = 1, b = -6, and c = -40.
The quadratic formula is given by:
x = (-b ± √(b^2 - 4ac))/(2a)
Plugging in the values we found, we get:
x = (-(-6) ± √((-6)^2 - 4(1)(-40)))/(2(1))
Simplifying further, we have:
x = (6 ± √(36 + 160))/2
x = (6 ± √196)/2
x = (6 ± 14)/2
Now we can solve for the two possible values of x:
x = (6 + 14)/2 = 20/2 = 10
x = (6 - 14)/2 = -8/2 = -4
Therefore, the solutions to the quadratic equation x^2 - 6x - 20 = 20 are x = 10 and x = -4.
Use the quadratic formula to solve the following quadratic equation: x2−6x−20=20
(1 point)
Responses
x = 10, x =− 4
x = 10, x =− 4
x = 3+210−−√, x =3−210−−√
x = 3+210−−√, x =3−210−−√
x = −10, x = 4
x = −10, x = 4
x = 52, x =− 46
1 answer