To find the length of LM, we first need to determine the length of AD and BC.
In a trapezoid, the midsegment is parallel to the bases and is equal to the average of the lengths of the bases. In this case, LM is parallel to AB and DC.
Given that AB = 50 and DC = 135, the average of these two bases is (50 + 135) / 2 = 185 / 2 = 92.5.
Now, let's focus on finding the lengths of AD and BC.
AD is the difference between the lengths of the bases and is equal to DC - AB = 135 - 50 = 85.
BC is equal to AD since trapezoid ABCD is an isosceles trapezoid (opposite sides are equal in length). So, BC = 85.
Since LM is parallel to AB and DC, and its length is equal to the average of the lengths of the bases, we have LM = (AB + DC) / 2 = (50 + 135) / 2 = 185 / 2 = 92.5.
However, we are asked to find a whole number as the answer. Since 92.5 is not a whole number, we need to round our answer.
Rounding 92.5 to the nearest whole number gives us LM = 93.
Therefore, the length of LM is 93.
LM¯¯¯¯¯¯¯¯¯is the midsegment of trapezoid ABCD. If AB =50 and DC = 135, what is LM? Please show all work in order to receive full credit for this problem the answer is a WHOLE NUMBER
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