Asked by Nikki
                (With a TI-89 calculator)
Graph x(t) = 3t^2 and y(t)=2-2t on [0,1]. Write a Cartesian equation that models this graph. Identify the initial and terminal points.
I graphed both equations, but I didn't really get what [0,1] meant. I think it's an interval. Also, with the Cartesian equation, I tried doing it algebraically:
y(t) = 2-2t
y-2 = -2t
t=(y-2)/-2
x=3[(y-2)/-2] ?
I'm also not sure about the terminal and initial point. Help please?
Thank you!
            
        Graph x(t) = 3t^2 and y(t)=2-2t on [0,1]. Write a Cartesian equation that models this graph. Identify the initial and terminal points.
I graphed both equations, but I didn't really get what [0,1] meant. I think it's an interval. Also, with the Cartesian equation, I tried doing it algebraically:
y(t) = 2-2t
y-2 = -2t
t=(y-2)/-2
x=3[(y-2)/-2] ?
I'm also not sure about the terminal and initial point. Help please?
Thank you!
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