To solve the equation x^2 - 2x - 35 = 0, we can use the quadratic formula. The quadratic formula states that for any equation of the form ax^2 + bx + c = 0, the solutions for x are given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this case, a = 1, b = -2, and c = -35. Plugging in these values into the quadratic formula, we get:
x = (-(-2) ± √((-2)^2 - 4(1)(-35))) / (2(1))
Simplifying further:
x = (2 ± √(4 + 140)) / 2
x = (2 ± √144) / 2
x = (2 ± 12) / 2
Therefore, the solutions for x are:
x = (2 + 12) / 2 = 14 / 2 = 7
x = (2 - 12) / 2 = -10 / 2 = -5
So, x can equal 7 or -5.
x2−2x − 35 = 0 for x.
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