Solve the compound inequality 5x+11≥−9 and 10x−3≤27

Answer 1

To solve 5x + 11 ≥ -9, we need to isolate x.

Subtracting 11 from both sides of the inequality, we get:
5x ≥ -20

To solve 10x - 3 ≤ 27, we need to isolate x.

Adding 3 to both sides of the inequality, we get:
10x ≤ 30

Now we can solve for x in both inequalities.

For 5x ≥ -20:
Dividing both sides by 5, we get:
x ≥ -4

For 10x ≤ 30:
Dividing both sides by 10, we get:
x ≤ 3

Therefore, the solution to the compound inequality is -4 ≤ x ≤ 3.