Asked by matrix school 2

note: E is for exponetial

two large horizontal, parallel metal plates are 2.5cm apart in air and the upper is maintained at a positive potential relative to the lower so that the field strenght between them is 2.1x10E3vmE-1

the potential difference between plates is 5.25x10E-1volts

Ques: If an electron of charge 1.8x10E-19C and mass 9.8x10E-31kg is liberated from rest at lower plate. find its speed on reaching the upper plate.

i got 4.3x10ms as answer

pls never sure if am right with this answer getting tough time with it.
Answered by bobpursley
The energy the electron receives is Vq, or 5.25E-1*1.6E-19 joules, and that is equal to 1/2 m v^2

v=sqrt 2(energy)/9,8E-31


I don't get your answer.
Answered by Joseph
8.57*10^-31
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