If the time I start at is 3:30 pm and the tempature is -0.4 degrees celcius and 3:45 pm after and the tempature goes to -1.9.Marley assumes that the temperature of the substance changed at a constant rate. According to Marley's assumption, at what time would the temperature of the substance have been 1.3°C?

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To determine the time at which the temperature of the substance would have been 1.3°C according to Marley's assumption, we need to find the rate at which the temperature is changing and then calculate the time difference.

First, let's calculate the rate of change in temperature:
Change in temperature = Final temperature - Initial temperature
Change in temperature = -1.9°C - (-0.4°C)
Change in temperature = -1.9°C + 0.4°C
Change in temperature = -1.5°C

Now, we need to find the time difference between the initial and final temperature:
Time difference = 3:45 pm - 3:30 pm = 15 minutes

Since the rate of change in temperature is constant, we can calculate the time it would take for the temperature to change by 1°C:
Time for 1°C change = Time difference / Change in temperature
Time for 1°C change = 15 minutes / -1.5°C
Time for 1°C change = -10 minutes/Celsius

Finally, we can calculate the time at which the temperature would have been 1.3°C:
Time = Initial time + (Time for 1°C change * Change in temperature)
Time = 3:30 pm + (-10 minutes/Celsius * (1.3°C - (-0.4°C)))
Time = 3:30 pm - 10 minutes/Celsius * 1.7°C
Time = 3:30 pm - 17 minutes
Time = 3:13 pm

According to Marley's assumption, the temperature of the substance would have been 1.3°C at 3:13 pm.
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