Asked by Diana

two cards are drawn without replacement from a 52 deck of cards. what ae the odds against drawing a club and a diamond? can you walk me through this? thank you
Answered by Marth
Why don't you attempt the problem first? I would be happy to critique your work.

Hint: keep in mind that while probability is the good/total, odds are the good/bad.
Answered by Garcia
D) 13 : 191
Answered by Marth
I'm not quite sure where you got 191.

Assuming you mean drawing a club and a diamond in that order:

the odds against drawing a club first are 39/13;
the odds against drawing a diamond next (without replacement) are 38:13;

So the odds against drawing a club and then a diamond are 39*38 : 13*13, or 114:13


If, however, you meant drawing a club and a diamond, in no particular order, then you must consider the odds against drawing a diamond first and then a club.

Those odds are the same as the odds against drawing a club first and then a diamond (as there are only 2 cards drawn), so just double the answer found above.

The odds against drawing a club and a diamond in no particular order are 114:26 or 57:13
Answered by Garcia
Well you see that answer does not match with one of the multiple choice rather it's and we know that it's not D so I'm assuming it's A then.

A) 204 : 13
B) 191 : 13
C) 13 : 204
D) 13 : 191
Answered by Diana
thank you for your help. The answer is A. Right?
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