Asked by Bri
x^6-y^6
fist look at as a difference of squares:
(x^3)<sup>2</sup> - (y^3)<sup>2</sup>
=(x^3 + y^3)(x^3 - y^3)
Now you have the sum of cubes and the difference of cubes, I assume you know the formulas for those. So you can keep going
(x+y)(x^2-xy+y^2)(x-y)(x^2+xy+y^2) would be your final answer.
fist look at as a difference of squares:
(x^3)<sup>2</sup> - (y^3)<sup>2</sup>
=(x^3 + y^3)(x^3 - y^3)
Now you have the sum of cubes and the difference of cubes, I assume you know the formulas for those. So you can keep going
(x+y)(x^2-xy+y^2)(x-y)(x^2+xy+y^2) would be your final answer.