Asked by Josh
Take q1=23uC at (0,1), q2=16uC. at (2,0), and q3=? at (2,2). IF the force on q1 points in the -x direction, (a) what is q3 and (b) what is the magnitude of the force on q1?
I know a is 16uC
For part B I got .067 am I right
I am using Coloumbs law
k=9.0*10^9
q1=23*10^-6
q2=16*10-6
r=7
What am I doing wrong??
I know a is 16uC
For part B I got .067 am I right
I am using Coloumbs law
k=9.0*10^9
q1=23*10^-6
q2=16*10-6
r=7
What am I doing wrong??
Answers
Answered by
bobpursley
You have to figure each force on q1 (from q3, q3) and add them as VECTORS.
Answered by
Josh
How do you do that
Answered by
bobpursley
Josh, if you don't know how to add two ninety degree vectors, and you are now in statics, something is greatly wrong.
http://www.glenbrook.k12.il.us/GBSSCI/PHYS/Class/vectors/u3l1b.html
http://www.glenbrook.k12.il.us/GBSSCI/PHYS/Class/vectors/u3l1b.html
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