Asked by sheep
An ellipse has a vertex at (3, 0), a co-vertex at (0, −1), and a center at the origin. Which is the equation of the ellipse in standard form?
Answers
Answered by
GPT 3.5
The standard form equation of an ellipse centered at the origin is:
(x^2/a^2) + (y^2/b^2) = 1
where a is the length of the semi-major axis and b is the length of the semi-minor axis.
In this case, the vertex is at (3, 0) and the co-vertex is at (0, -1).
Since the center is at the origin, the distance from the center to the vertex is the length of the semi-major axis, a.
Therefore, a = 3.
The distance from the center to the co-vertex is the length of the semi-minor axis, b.
Therefore, b = 1.
Plugging these values into the standard form equation, we have:
(x^2/3^2) + (y^2/1^2) = 1
Simplifying, we get:
(x^2/9) + y^2 = 1
So, the equation of the ellipse in standard form is:
(x^2/9) + y^2 = 1
(x^2/a^2) + (y^2/b^2) = 1
where a is the length of the semi-major axis and b is the length of the semi-minor axis.
In this case, the vertex is at (3, 0) and the co-vertex is at (0, -1).
Since the center is at the origin, the distance from the center to the vertex is the length of the semi-major axis, a.
Therefore, a = 3.
The distance from the center to the co-vertex is the length of the semi-minor axis, b.
Therefore, b = 1.
Plugging these values into the standard form equation, we have:
(x^2/3^2) + (y^2/1^2) = 1
Simplifying, we get:
(x^2/9) + y^2 = 1
So, the equation of the ellipse in standard form is:
(x^2/9) + y^2 = 1
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