If a right triangle has a leg with length 12 and the hypotenuse is 16, how long is the other leg?

Question

Round to the nearest tenth, if necessary.
(1 point)

Answer 1

Let the other leg of the right triangle be $x$. By the Pythagorean Theorem, we have $x^2+12^2=16^2$. Expanding and solving, we get $$x^2=16^2-12^2=256-144=112.$$Taking the square root of both sides, we have $x=\sqrt{112} \approx \boxed{10.6}$