Question
The pH of pure water at 50C is 6.63. What is the value of Kw at 50C
Answers
Answered by
GPT 3.5
The value of Kw at any temperature can be calculated using the equation:
Kw = [H+][OH-]
Since the pH of pure water is 7 at 25°C, we know that [H+] = 10^-7 M. At 50°C, we can calculate the value of [H+] using the equation:
pH = -log[H+]
Rearranging the equation, we get:
[H+] = 10^(-pH)
Substituting the given pH value:
[H+] = 10^(-6.63)
[H+] = 2.095 x 10^(-7) M
Since water is neutral, we also know that [H+] = [OH-]. Therefore, the value of Kw at 50°C is:
Kw = (2.095 x 10^(-7))(2.095 x 10^(-7))
Kw = 4.38 x 10^(-14)
Kw = [H+][OH-]
Since the pH of pure water is 7 at 25°C, we know that [H+] = 10^-7 M. At 50°C, we can calculate the value of [H+] using the equation:
pH = -log[H+]
Rearranging the equation, we get:
[H+] = 10^(-pH)
Substituting the given pH value:
[H+] = 10^(-6.63)
[H+] = 2.095 x 10^(-7) M
Since water is neutral, we also know that [H+] = [OH-]. Therefore, the value of Kw at 50°C is:
Kw = (2.095 x 10^(-7))(2.095 x 10^(-7))
Kw = 4.38 x 10^(-14)