moles H+=.02*.10+.01*.50
volume= .03liters
concentration= moles/liters
volume= .03liters
concentration= moles/liters
First, let's determine the number of moles of H+ in each solution. To do this, multiply the volume of each solution by its concentration:
Number of moles of H+ in 20 mL of 0.100 M HCl:
Moles = Volume (L) x Concentration (M)
Moles = (20 mL / 1000 mL/L) x 0.100 M
Moles = 0.002 mol
Number of moles of H+ in 10.0 mL of 0.500 M HCl:
Moles = Volume (L) x Concentration (M)
Moles = (10.0 mL / 1000 mL/L) x 0.500 M
Moles = 0.005 mol
Now, let's calculate the total moles of H+ in the mixed solution by adding the moles of H+ from each of the solutions:
Total moles of H+ = Moles from 0.100 M HCl + Moles from 0.500 M HCl
Total moles of H+ = 0.002 mol + 0.005 mol
Total moles of H+ = 0.007 mol
Finally, to determine the concentration of H+ in the mixed solution, divide the total moles of H+ by the total volume of the mixed solution:
Concentration (M) = Total moles of H+ / Total volume (L)
The total volume of the mixed solution is the sum of the volumes of the two solutions:
Total volume = 20 mL + 10.0 mL = 30.0 mL
Converting this to liters:
Total volume (L) = 30.0 mL / 1000 mL/L = 0.030 L
Now we can calculate the concentration of H+ in the mixed solution:
Concentration (M) = 0.007 mol / 0.030 L
Concentration (M) = 0.233 M
Therefore, the concentration of H+ in the solution formed by mixing 20 mL of 0.100 M HCl and 10.0 mL of 0.500 M HCl is 0.233 M.