3s+5n = 1790
s = 2n-100
(s,n) = (190,280)
Tickets to the school musical cost $3 for students and $5 for non students. Total ticket sales were $1790. The number of student tickets sold was 100 less than twice the number of non student tickets sold.
Write a system of equations to represent this situation. Solve the system of equations. How many student tickets sold? How many non students?
2 answers
5n + 3n = 1790
n= tickets sold for non student
2n-100 = tickets sold for student
So,
5n + 3(2n-100)= 1790
5n + 6n - 300 = 1790
11n = 1790+300
11n= 2090
n= 190
So, substituting the value of n we 5(190)+ 3(2(190)-100) =1790
950 + 840 =1790
n= tickets sold for non student
2n-100 = tickets sold for student
So,
5n + 3(2n-100)= 1790
5n + 6n - 300 = 1790
11n = 1790+300
11n= 2090
n= 190
So, substituting the value of n we 5(190)+ 3(2(190)-100) =1790
950 + 840 =1790
2 answers