To calculate the concentration of the peroxide solution, we can use the stoichiometric ratio between MnO4- and H2O2. According to the balanced chemical equation:
2 MnO4- + 5 H2O2 + 6 H+ -> 2 Mn2+ + 5 O2 + 8 H2O
We can see that for every 2 moles of MnO4-, we need 5 moles of H2O2. Therefore, the molar ratio is 2:5.
Since we know the volume of KMnO4 is 0.0106 L, we can determine the number of moles of MnO4- by multiplying the volume by the concentration.
Let's assume the concentration of KMnO4 is x M.
Number of moles of MnO4- = Concentration x Volume
Number of moles of MnO4- = x M * 0.0106 L
Number of moles of MnO4- = 0.0106 x M
According to the stoichiometry, the number of moles of H2O2 will be:
Number of moles of H2O2 = (5/2) * Number of moles of MnO4-
Number of moles of H2O2 = (5/2) * (0.0106 x M)
Finally, to calculate the concentration of H2O2, we divide the number of moles by the volume (which is 0.0106 L):
Concentration of H2O2 (in M) = Number of moles of H2O2 / Volume
Concentration of H2O2 (in M) = (5/2) * (0.0106 x M) / 0.0106 L
Concentration of H2O2 (in M) = 5/2 * M
Therefore, the concentration of the peroxide solution is 5/2 times the concentration of KMnO4.
2 MnO4- + 5 H2O2 + 6 H+ -> 2 Mn2+ + 5 O2 + 8 H2O
calculate the concentration of the peroxisw solution
Volume of KMnO4 is 0.0106L
1 answer