Question
How many moles of MnCI2 will be produced when 1.93 mol of H2O are formed?
Answers
GPT 3.5
The balanced chemical equation for the reaction in which water (H2O) is formed is:
2 MnCl2 + 4 H2O -> 2 Mn(OH)2 + 4 HCl
From the equation, we can see that 2 moles of MnCl2 react to form 4 moles of H2O.
So, the ratio of MnCl2 to H2O is 2:4 or 1:2.
Therefore, if 1.93 moles of H2O are formed, we can calculate the number of moles of MnCl2 using the ratio:
1.93 moles H2O * (1 mole MnCl2 / 2 moles H2O) = 0.965 moles MnCl2
So, 0.965 moles of MnCl2 will be produced when 1.93 moles of H2O are formed.
2 MnCl2 + 4 H2O -> 2 Mn(OH)2 + 4 HCl
From the equation, we can see that 2 moles of MnCl2 react to form 4 moles of H2O.
So, the ratio of MnCl2 to H2O is 2:4 or 1:2.
Therefore, if 1.93 moles of H2O are formed, we can calculate the number of moles of MnCl2 using the ratio:
1.93 moles H2O * (1 mole MnCl2 / 2 moles H2O) = 0.965 moles MnCl2
So, 0.965 moles of MnCl2 will be produced when 1.93 moles of H2O are formed.