Question

Which of the following describe the correct procedure to prepare 1.50 L of 1.00 M KMnO4 (aq)? (The molar mass of KMnO4 is 158 g/mol)

Answer 1

To prepare 1.50 L of 1.00 M KMnO4 (aq), you will need to determine the amount of KMnO4 (in grams) required.

1. First, calculate the number of moles needed using the molarity and volume of the solution:
Moles of KMnO4 = Molarity × Volume
Moles of KMnO4 = 1.00 M × 1.50 L = 1.50 moles

2. Next, convert moles to grams using the molar mass of KMnO4:
Grams of KMnO4 = Moles of KMnO4 × Molar Mass
Grams of KMnO4 = 1.50 moles × 158 g/mol = 237 g

3. Dissolve 237 grams of KMnO4 in enough water (distilled or deionized) to make 1.50 L of solution.