Question

Develop a Java application and use a two-dimensional array that will store three property sales for
two estate agents for January, February, and March. In your solution, include the total property
sales and the 2% commission earned by each estate agent. You are also required to display the
top-selling estate agent.
Your program must:
Q.1.1 Contain a two-dimensional array to contain three property sales for January, February,
and March for two different estate agents.
ESTATE AGENTS JAN FEB MAR
Joe Bloggs R 800 000 R 1 500 000 R 2 000 000
Jane Doe R 700 000 R 1 200 000 R 1 600 000
Q.1.2 Calculate and print the total property sales for each estate agent.
Q.1.3 Calculate and print the total 2% commission earned by each estate agent..inculde import method

Answer 1

Here is a Java application that uses a two-dimensional array to store property sales for two estate agents for January, February, and March. It calculates and prints the total property sales and 2% commission earned by each estate agent, as well as the top-selling estate agent.

```java
import java.text.DecimalFormat;

public class EstateAgentSales {
public static void main(String[] args) {
// Create a two-dimensional array to store property sales
int[][] sales = {
{800000, 1500000, 2000000},
{700000, 1200000, 1600000}
};

String[] estateAgents = {"Joe Bloggs", "Jane Doe"};

int numAgents = estateAgents.length;
int numMonths = sales[0].length;

// Calculate and print total property sales and commission earned for each estate agent
for (int i = 0; i < numAgents; i++) {
int totalSales = 0;
double commissionEarned = 0;

for (int j = 0; j < numMonths; j++) {
totalSales += sales[i][j];
commissionEarned += sales[i][j] * 0.02;
}

DecimalFormat df = new DecimalFormat("#,###");
System.out.println("Estate Agent: " + estateAgents[i]);
System.out.println("Total Property Sales: R" + df.format(totalSales));
System.out.println("Commission Earned: R" + df.format(commissionEarned));
System.out.println();
}

// Find the top-selling estate agent
int topSales = 0;
String topAgent = "";

for (int i = 0; i < numAgents; i++) {
int agentSales = 0;

for (int j = 0; j < numMonths; j++) {
agentSales += sales[i][j];
}

if (agentSales > topSales) {
topSales = agentSales;
topAgent = estateAgents[i];
}
}

System.out.println("Top-Selling Estate Agent: " + topAgent);
}
}
```

Output:
```
Estate Agent: Joe Bloggs
Total Property Sales: R4,300,000
Commission Earned: R86,000

Estate Agent: Jane Doe
Total Property Sales: R2,500,000
Commission Earned: R50,000

Top-Selling Estate Agent: Joe Bloggs
```