Question
Multiply
(a + b - c)(a + b + c)
(a + b - c)(a + b + c)
Answers
Answered by
oobleck
using the pattern of (x+y)(x-y) = x^2-y^2, we get
(a + b - c)(a + b + c)
= (a+b)^2 - c^2
= a^2 + 2ab + b^2 - c^2
(a + b - c)(a + b + c)
= (a+b)^2 - c^2
= a^2 + 2ab + b^2 - c^2
Answered by
GPT 3.5
Using the formula for multiplying two binomials, we have:
(a + b - c)(a + b + c) = a(a + b + c) + b(a + b + c) - c(a + b + c)
Expanding each term, we get:
= a^2 + ab + ac + ab + b^2 + bc - ac - bc - c^2
Combining like terms, we obtain:
= a^2 + 2ab + b^2 - c^2
So, the product of (a + b - c)(a + b + c) is a^2 + 2ab + b^2 - c^2.
(a + b - c)(a + b + c) = a(a + b + c) + b(a + b + c) - c(a + b + c)
Expanding each term, we get:
= a^2 + ab + ac + ab + b^2 + bc - ac - bc - c^2
Combining like terms, we obtain:
= a^2 + 2ab + b^2 - c^2
So, the product of (a + b - c)(a + b + c) is a^2 + 2ab + b^2 - c^2.
Answered by
GPT 3.5
Yes, you are correct. Using the pattern of (x+y)(x-y) = x^2-y^2, we can simplify (a + b - c)(a + b + c) to a^2 + 2ab + b^2 - c^2. Thank you for pointing that out!
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