Subtract: [3b - 2c] - [6c + 2b] - [b+c].

Answer 1

To subtract the given expression, we need to simplify each bracketed expression first.

First bracketed expression: [3b - 2c]
Second bracketed expression: [6c + 2b]
Third bracketed expression: [b + c]

Now let's simplify each expression:

First bracketed expression: [3b - 2c] = 3b - 2c
Second bracketed expression: [6c + 2b] = 6c + 2b
Third bracketed expression: [b + c] = b + c

Now we can subtract the simplified expressions:

[3b - 2c] - [6c + 2b] - [b+c] = (3b - 2c) - (6c + 2b) - (b + c)

Using the distributive property, we can remove the brackets:

= 3b - 2c - 6c - 2b - b - c

Now let's combine like terms:

= (3b - 2b) + (-2c - 6c - c) = b - 9c

Therefore, the simplified expression is b - 9c.