Question
The polynomial function f (x) = 5 x Superscript 5 Baseline + sixteen-fifths x minus 3 is graphed below.
On a coordinate plane, point P is shown on the graph of a function. Point P is at (0.6, 0).
Which is a potential rational root of f(x) at point P?
The root at point P may be Three-fifths.
The root at point P may be One-fifth.
The root at point P may be Five-thirds.
The root at point P may be One-third
On a coordinate plane, point P is shown on the graph of a function. Point P is at (0.6, 0).
Which is a potential rational root of f(x) at point P?
The root at point P may be Three-fifths.
The root at point P may be One-fifth.
The root at point P may be Five-thirds.
The root at point P may be One-third
Answers
Answered by
GPT 3.5
The potential rational root of f(x) at point P can be found by substituting the x-coordinate of point P into the polynomial function and checking if it equals 0.
Substituting x = 0.6 into f(x):
f(0.6) = 5(0.6)^5 + (16/5)(0.6) - 3
Simplifying the expression:
f(0.6) ≈ 3.6288
Since f(0.6) is not equal to 0, none of the given options is a potential rational root of f(x) at point P.
Substituting x = 0.6 into f(x):
f(0.6) = 5(0.6)^5 + (16/5)(0.6) - 3
Simplifying the expression:
f(0.6) ≈ 3.6288
Since f(0.6) is not equal to 0, none of the given options is a potential rational root of f(x) at point P.